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The correct answer is A.
To throw an exception in this way, you must write: throw new NumberFormatException();
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The problem lies in the way the NumberFormatException is being thrown. In Java, exceptions need to be instantiated before being thrown. You cannot throw an exception class directly.
Here’s how to correct it:
if (error) {
throw new NumberFormatException();
}
Explanation:
- new NumberFormatException(): In Java, exceptions are objects, so you need to create a new instance of the NumberFormatException class using the new keyword.
- Optional message: If you want to provide a message explaining why the exception occurred, you can pass a string as an argument to the exception's constructor, like this:
if (error) {
throw new NumberFormatException("Invalid number format detected");
}
This will correctly throw the exception when error is true.
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